A 1400 kg steel beam is supported by two ropes. 

What is Tension in Rope 1 and what is Tension in Rope 2
Answer
Along the x - direction:
T1 sin20 = T2
sin30
0.342 T1 = 0.5T2
==> T1 / T2 = 0.5 / 0.342
T1
= 1.461T2 ........1
Along the vertical direction
T1cos20 + T2 cos30
=mg
==> 0.939T1 + 0.866T2 =
13720 .....2
Substituting 1 in 2 we get
1.3718T2
+0.866T2 = 13720
2.237
T2 = 13720
∴
T2 = 6133.2 N
and
T1 = 8960.2 N
T1sin(20) = T2sin(30)
T1cos(20) + T1cos(30) = mg
T1cos(20) + T1sin(20)cos(30)/sin(30) =
mg
T1cos(20)sin(30) + T1sin(20)cos(30)
=mgsin(30)
T1sin(20 + 30) = mgsin(30)
∴T1 = mgsin(30)/sin(50) = 8955 N
T2 = mgsin(20)/sin(50) = 6126 N