A cell has a standard emf of + 0.166 V at 298 K.?

What is the value of the equilibrium constant for the cell reaction if n=2?

What is the value of the equilibrium constant for the cell reaction if n=3?

1 Answer

  • Eo = RT/nF * ln(K)

    (Eo * nF)/RT = ln(K)

    (0.166V * 2mol*e- * 9.65E4C/mol*e)/(8.314J/molK * 298K) = ln(K)

    12.93 = lnK

    e^12.93 = e^lnK

    4.13E5 = K

    Same principle for the second part

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