a small object moves along the x-axis with acceleration ax(t)
=-(0.0320m/s3)(15.0s-t). at t=0 the object is at x=-14.0m and has
velocity v0x =4.50 m/s. what is the x-coordinate of the object when
t=10.0s?
=-(0.0320m/s3)(15.0s-t). at t=0 the object is at x=-14.0m and has
velocity v0x =4.50 m/s. what is the x-coordinate of the object when
t=10.0s?
Answer
The accelerati on is -(0.0320m / s3) (15.0s-t) dv=-(00320m/s*)(150s-t) dv=-(0.0320m /s3)(150s-t)dt Integrate the equation. (0320m/15- dt=v,-(0.0320m/S3115- Integrate the equation 1021 「103 X=-14 + (4.5)(10)-(0.0320m / s*)| 15| | -11 x 12.33 nm