An aluminum sphere is 8.35 cm in diameter.?

2 Answers

• Change in volume = (Coefficient of volume expansion) x (Original volume) x (Change in temperature)

  Original volume = 4/3(pi)(r)^3 where r= 4.175cm, and this would make V= 304.8 cm^3.

  For aluminum, the coefficient of volume expansion is 75x10^-6 /degC. (This is three times the coefficent of linear expansion).

  The change in temperature is 200-30 = 170 degC.

  Plugging it in,

  Change in volume = (75x10^-6 /degC) x (304.8 cm^3) x (170 degC)

  Change in volume = 3.887 cm^3.

  Hope this helps, and I hope all my math is right. 🙂

  Source(s): Giancoli's book, "Physics for Scientists & Engineers with Modern Physics 4th ed."
  Chapter 17.4, on pages 460-461.

• Aluminum Sphere