An earth satellite moves in a circular orbit with an orbital speed of 6300 m/s.?

a) Find the time of one revolution of the satellite.

b) Find the radial acceleration of the satellite in its orbit.

1 Answer

  • T = 2pi*r/v

    r = GM/v^2

    T = 2pi*GM/v^3 = 2pi*gR^2/v^3

    R = 6400000 m

    T = 10090 s = 2.8 hr

    a = v^2/r = v^4/GM = v^4/gR^2 = 3.9 m/s^2

    Answer:

    a) 2.8 hr

    b) 3.9 m/s^2

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