Calculate the empirical formula of the hydrocarbon.?

Combustion analysis of a hydrocarbon produced 33.01g CO2 and 4.83g H2O

1 Answer

  • mass of CO2 = 33.01 g or since the molar mass of CO2 is 44g / mole we have

    0.75006 moles of CO2 since there is 1 mole so C in CO2

    we have 0.75006 moles of C or 9.008 g of C

    mass of H2O = 4.83 g or since the molar mass of water is 18 g / mol we have

    0.26811 moles of H2O since there are2 moles of H in 1 moles of H2O =

    0.53621 moles of H or 0.540 g of H

    molar ratio of C : H = 0.75006 : 0.53621

    mass of C+H = 9.549 g

    or after dividing by the smallest 0.53621

    molar ratio of C : H = 1.399 : 1.000

    multiply by 5 to get whole numbers 6.994 5.000

    empirical formula is C7H5 ?? : data problems..

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