A 4.6 m aqueous solution of an ionic compound with the
formula MX2 has a boiling point of 101.8 ?C.
-Calculate the van't Hoff factor (i) for MX2 at this
Elivation in boiling point ,
elivation is boiling point of water
= Boiling point of
solution - Boiling point of water
= 101.8 - 100.0
i = van't Hoff factor = ?
Kb = elivation in boiling point of water = 0.512
m = molality of solution = 4.6 m
Plug the values we get
Therefore van't Hoff factor for MX2 is 0.76