Calculate the van’t hoff factor (i) for mx2 at this concentration.

Answer

Elivation in boiling point ,

Where

=
elivation is boiling point of water

        = Boiling point of
solution - Boiling point of water

        = 101.8 - 100.0
^oC

        = 1.8
^oC

i = van't Hoff factor = ?

K_b = elivation in boiling point of water = 0.512
^oC/m

m = molality of solution = 4.6 m

Plug the values we get

Therefore van't Hoff factor for MX₂ is 0.76