8th grade math, ive been sitting ere for 2 hours and i need someone to explain it.

ok,

21(2-x)+12x=44

• first distribute the 21

42 - 21x + 12x = 44

combine the x's

42 - 9x = 44

then subtract 42 from both sides

-9x = 2

divide both sides by -9

x = -2/9

• First, you distribute the 21 to everything in the parenthesis. That would give you 42-21x+12x=44.

Second, you combine like terms: 42-9x=44

Third, subract 42 from boith sides: -9x=2

Fourth, divide both sides by -9: x= 2/-9

Source(s): Im an eighth grader in algebra 1
• ok. here are the steps and how they're done.

1. 42 - 21x + 12x = 44. (distributive property.)

2. 42 - 9x = 44 (-21x + 12x)

3. -9x = 2 (subtract 42 from both sides)

4. x = -2/9 (divide both sides by -9)

if that's not right, well it's late, I'm tired, and I did that in my head.

• step one: distribute the 21 over the (2-x). so you have 42+21x+12x=44.

step two: combine like-terms; add the 21x and 12x together. now you have 42+33x=44.

step three: subtract the 42 from both sides, now you have 33x=2.

step four: divide both sides by 33 and you have x=2/33

• multiply (2-x) by 21 to get 42-21x+12x=44

combine like terms of -21x and 12x to get 42-9x=44

get the variable alone on one side by first subtracting 42 on both sides to get -9x=2

then get the variable alone further by dividing -9 on both sides to get x=negative 2/9

i hope this helps

• it's very easy......

21(2)+21(-x)+12x=44

42-21x+12x=44

42-44=21x-12x

-2=9x

x=-2/9

• try paying attention in class