8th grade math, ive been sitting ere for 2 hours and i need someone to explain it.
ok,
21(2-x)+12x=44
7 Answers
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first distribute the 21
42 - 21x + 12x = 44
combine the x's
42 - 9x = 44
then subtract 42 from both sides
-9x = 2
divide both sides by -9
x = -2/9
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First, you distribute the 21 to everything in the parenthesis. That would give you 42-21x+12x=44.
Second, you combine like terms: 42-9x=44
Third, subract 42 from boith sides: -9x=2
Fourth, divide both sides by -9: x= 2/-9
Source(s): Im an eighth grader in algebra 1 -
ok. here are the steps and how they're done.
1. 42 - 21x + 12x = 44. (distributive property.)
2. 42 - 9x = 44 (-21x + 12x)
3. -9x = 2 (subtract 42 from both sides)
4. x = -2/9 (divide both sides by -9)
if that's not right, well it's late, I'm tired, and I did that in my head.
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step one: distribute the 21 over the (2-x). so you have 42+21x+12x=44.
step two: combine like-terms; add the 21x and 12x together. now you have 42+33x=44.
step three: subtract the 42 from both sides, now you have 33x=2.
step four: divide both sides by 33 and you have x=2/33
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multiply (2-x) by 21 to get 42-21x+12x=44
combine like terms of -21x and 12x to get 42-9x=44
get the variable alone on one side by first subtracting 42 on both sides to get -9x=2
then get the variable alone further by dividing -9 on both sides to get x=negative 2/9
i hope this helps
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it's very easy......
21(2)+21(-x)+12x=44
42-21x+12x=44
42-44=21x-12x
-2=9x
x=-2/9
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try paying attention in class