Consider the following reaction
8A(g) + 5B(g) → 8C(g) + 6D(g)
If [C] is increasing at the rate of 4.0 mol L-1s-1, at what rate is [B] changing?
Question 2 answers
As can be seen from the equation, 8 moles of A and 5 moles of B combine to produce 8 moles of C and 6 moles of D.
rate of change of [C]/ 8 = rate of change of [B] /5
rate of change of [B] = 5 * 4/8 = 2.5 mol L-1 s-1
Hope this helps!
rB/rC=5/8 RB=5/8 * rC=5/8 * 0.4=0.25