Consider the reaction: 2H2S(g) + 3O2(g) → 2SO2(g) + 2H2O(g)?

Use data in table below

Compound S°, J·mol-1·K-1

H2S(g) 206

O2(g) 205.0

SO2(g) 248

H2O(g) 188.7

calculate ΔS° in J·K-1....

2 Answers

  • its just ΔS°products - ΔS°reactants.

    so its (2x248+2x188.7) - (2x206+3x205)

  • ΔS = ΔS°products - ΔS°reactants.

    (2x248+2x188.7) - (2x206+3x205)

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