During the discharge of an alkaline battery, 4.90g of Zn..How many coulombs of electrical charge are transferred from Zn to MnO2?

1 Answer

• each zinc atom transfers two electrons

  4.90 g * 1 mol Zn / 65.39 g * 2 mol e- / 1 mol Zn = 0.14987 mol e-

  a mole of charge is called a Faraday

  and there are 96485 C/F

  0.14987 F * 96485 C/F = 1.45E4 C to 3 sig figs

  If someone gives you a good response,

  please consider giving a best answer.

  This is the only reward we get.