3 Answers
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8
Let x = the first integer
Then x+1 = the second integer
And x+(x+1)>16.
Solve the inequality:
2x+1 > 16
2x > 15
x > 15/2
Since x is an integer...
x = 8
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x = integer
x + 1 = next consecutive integer
x + x + 1 > 16
2x + 1 > 16
2x > 15
x > 7.5
least integer x can be is 8
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x+(x+1) = 2x+1 >= 17
2x >= 16
x>= 8
the smaller of the two is at least 8
