Find the output voltage for the attached circuit. introduce your answer as a number in volts.

Using super position theorem considering only 6 v source at -ve terminal and shorting the 2 v source V_0/V_1 = -R_f/R = V_01 = -(100/10) times 6 = -60 V Now considering 2 V source and shorting 6 v source V_02/2 = (1 + R t/R) = (1 + 100/10) = 11 times 2 = 22 V V_0 = V_01 + V_02 = -60 + 22 = -38 V