Given that an = 3an – 1 + 1, where a1 = 2, find the 3rd-6th terms of the sequence.

Given that an = 3an - 1 + 1, where a1 = 2, find the 3rd-6th terms of the sequence.

A) 2, 7, 22, 67

B) 7, 22, 67, 202

C) 22, 67, 202, 607

D) 67, 202, 607, 1822

thank you!

1 Answer

  • if

    a1 = 2,

    then

    a2 = 3a1 + 1

    a3 = 3a2 + 1 = 3(3a1 + 1) + 1 = 9a1 + 4 = 9(2) + 4 = 22

    So we know the first term is going to be 22. The only answer with that available is (c). You can use your formula to find a4, a5 and a6 to confirm if you like.

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