how do you solve 3log2x=4? please explain also..?

7 Answers

  • Inverse of a log is 10^x so therefore we can solve using a bit of algebra:

    3log2x=4

    log2x=4/3 -- Divide by 3 on both sides

    2x=10^(4/3) -- Inverse of log is 10^x. Apply to both sides

    x={10^(4/3)}/2 -- Divide both sides by 2

    Now solve.

    x = 10.77217345 or about that.

    We can sub in for X to see that is correct.

    3log2{10.77217345}=4

  • Hi. I just trimmed your question to "How do you solve 3log2x=4?" and entered it in to my browser and this was the result. It apparently had been asked previously and Yahoo! Answers.

    http://answers.yahoo.com/question/index?qid=200904...

    Solve 3log2x = 4. round to the nearest ten-thousanth.? - Yahoo ...

    Apr 11, 2009 ... Block User. Best Answer - Chosen by Voters ...

    answers.yahoo.com › Science & Mathematics › Mathematics - Cached

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  • Assuming "log" is the base 10 log...

    3 log 2x = 4

    log 2x = 4/3

    10^ (log 2x) = 10^ (4/3)

    2x = 10 ^ (4/3)

    x = (10 ^ (4/3)) / 2

    x = one half the cube root of 10000

    If it's the natural log (base e) then the answer is

    (e ^ (4/3)) /2

  • it depends on if you mean 3log(2x) = 4, or 3log(base2)x = 4. in either case, the first step is to divide by 3. if you are talking about (natural) log(2x), you would then exponentiate (by e) to obtain:

    2x = e^(4/3), so x=(e^(4/3))/2. if however, you are talking about log(base2)x, you would have:

    x = 2^(4/3), or twice the cube root of 2.

  • 2^3log2x=2^4

    2^log2x^3=2^4

    x^3=2^4

    x^3=2*2^3

    x=2*2^(1/3)

    x=2^(4/3)

  • sorry, you didn't write the question in a specific way.

    is it log base 2x? log base 2? log base 10?

    Sorry

  • When writing an equation, please be precise, especially with log function. Is it base 2 or base e?

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