how would you Write 88 as a product of prime factors.?

10 Answers

• Make a factor tree.

  88=44*2

  44=22*2

  22=11*2

  Neither 11 or 2 have any other prime factors.

  So

  88=222*11

• Prime Factorization Of 88

  Source(s): https://shorte.im/bbqXg

• all that it means is find the prime factorization

  88/2 =44

  44/2 =22

  22/2 =11

  2x2x2x11=88

  so, 2x2x2x11=88 is the answer

• Check out my eHow article on how to do prime factorization, which is what this problem is about:

  http://www.ehow.com/how_4776386_do-prime-factoriza...

  Prime numbers are 2,3,5,7,11,13,17,19,...

  88=8*11 but 8 is not prime.

  88=(42)11 but 4 is not prime.

  88=222*11; this is the answer. All factors are prime.

  Source(s): http://www.ehow.com/how_4776386_do-prime-factoriza...

• 2^3 x 11

  Proof:

         88/2 = 44
  
         44/2 = 22
  
         22/2 = 11
  
         11/11 = 1

  The divisors are 2, 2, 2 and 11

  So the awnser is: 2^3 x 11

• 2^3 x 11

• Here's a visual factor tree for 88:

  http://mathvine.com/pre-algebra/prime-factorizatio...

• 2^3 * 11

• Just use any number of prime numbers to reach it using multiplication, such as 2,3,7,11 etc.

  You could say 2x2x2x11, for example.

• 2x2x2x11