Consider the following reaction.
A (aq) <==> 2B (aq)
(<==> to show equilibrium sign)
Kc = 8.87*10^-6 at 500K
1 Answer
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K = B^2/2.8= 8.87*10^-6
so
B = 4.98*10^-3 M
Consider the following reaction.
A (aq) <==> 2B (aq)
(<==> to show equilibrium sign)
Kc = 8.87*10^-6 at 500K
K = B^2/2.8= 8.87*10^-6
so
B = 4.98*10^-3 M