If container A holds 8 gallons of water and container B holds 12% more than container A, how many gallons of water does container B hold?

3 Answers

  • If Container A Holds 8 Gallons

  • 8 gallons * (1 + 12%) = 8 gallons * 1.12 = 8.96 gallons

  • B = A+A*0.12 = A(1+0.12) = 8.0*1.12 = 8+0.96 = 8.96 gals

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