Planet Z is 12,000 km in diameter. The free-fall acceleration on Planet Z is 9.0 m/s2.?

4 Answers

• (a) g=Gm/r^2 where G=6.67 * 10^-11 Nm^2/kg^2, m is the mass of the planet, r is the radius of the planet.

  9.0 = (6.67 10^-11)/(6000^2) m

  m= (6000000^2 9.0)/(6.67 10^-11)

  m~4.85757*10^24 kg

  (b) g=Gm/r^2. This time, the radius is 6000+10000 = 16000km

  g=(6.67 10^-11 4.85757*10^18)/(16000^2)

  g ~1.26562 m/s^2

  To the person below thanks for reminding me.

• Planet Z

  Source(s): https://shorte.im/bccHc

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• gearth= G* Mearth/ (earth radius)^2

  gplanetZ=G* Mplanetz/ (planetz radius)^2

  G is a universal constant

  (a)

  gearth=9.8 m/s^2

  gplanetz=9 m/s^2

  earth radius= 6371 * 10^3 m

  planetz radius= 6000 *10 ^3 m

  Mearth=5.9742 × 10^24 kg

  Divide both equations you get

  Mplanetz= gplanetz/gearth (radius planet z)^2/(radius earth)^2 Mearth

  Mplanetz=4.87 x 10^24 kg

  b)

  gplantz= G*Mplanetz/(radius planet z)^2

  gatheight= G*Mplanetz/(radius planet z + h)^2

  gatheight=gplanetz (radius planet z)^2/(radius planet z + h)^2= 9 6000^2/16000^2

  gatheight=1.26 m/s^2

  catsponge: you forget to convert to meter in part a