solve..expand whatever can someone please just show me how to get to the final product and why you did what you did to get to the final product...i don't understand where the 12xy is coming from becasue i got (9x)sq  (4y)sq...thanks everyone for the help
omg thanks a bunch KP i forgot about foil.....im refreashing myself for a college placement exam and i haven't done math in years
refreshing
8 Answers

Since (3x  2y)² yields the perfect square trinomial, we use this formula..
(a  b)² = a²  2ab + b²
Hence, we have..
(3x  2y) = (3x)²  2(3x)(2y) + (2y)²
= 9x²  12xy + 4y²
I hope this helps!
Source(s): Knowledge 
(3x2y)^2 is the same as (3x2y)(3x2y)
FOIL >> 9x^2  12xy + 4y^2
another quick way to do it would be to take (3x2y)^2
square the first term 9x^2
multiply the first term by the second term and then multiply that by 2, 12xy
square the second term, 4y^2
so you end up with the same answer as the FOIL method, 9x^2 12xy +4y^2

(ab)^2 = a^2  2ab + b^2
(3x  2y)^2 = 9x^2  12xy + 4y^2

(just an attempt)
Eerything im the brackets will be squared
So,
9x4y
Im not sure if you leave it at that or if it then becomes 5xy but i think you leave it as 9x4y. I really hope i helped lol

Solve what? That's not an equation. If you want me to expand it...
(3x  2y)Â²
(3x)Â² + 2(3x)(2y) + (2y)Â²
9xÂ²  12xy + 4yÂ²

(Ab)sq =a^22ab+b^2
So 3x2y sq
=9x^212xy+4y^2

expand it become (3x 2y) (3x2y) then, become 3x in the first bracket times 3x in the second bracket so, it becomes 9x square. then the 3x in the first bracket times with the 2y in the second bracket. so it becomes 6xy. so, 9x square 6xy. then, the 2y in the first bracket times with the 3x in the second bracket and becomes 6xy. so far, it becomes 9x square 6xy 6xy. then, the 2y in the first bracket times with the 2y in the second bracket and becomes +4y square. so, combined, then becomes, 9x square6xy6xy+4ysquare. then, simplify becomes 9x square12xy+4ysquare

( 3x  2y ) ( 3x  2y )
9 x Â²  6 xy  6 xy + 4 y Â²
9 x Â²  12 xy + 4 y Â²