Rearrange this expression into quadratic form, ax^2+bx+c = 0 0.20 = x^2/85-x a = 1, and identify the values of b and C. a = 1 b = 0.2 c = 11

## Answer

## General guidance

Concepts and reason

The quadratic polynomial is a second order polynomial of the form, . If this polynomial is to zero, then it is called quadratic equation.

In quadratic equation, , but b and c may equal to 0.

Fundamentals

The quadratic equation is in the form of , . Here, are the coefficients.

## Step-by-step

### Step 1 of 2

Rearrange the given expression as follows:

The given expression is as follows:

This equation is rearranged in the form of .

### Step 2 of 2

Compare the equation with to get the values of b and c as follows:

The values of are as follows:

The values of are as follows:

The coefficients in the following two equations are compared to get the values of b and c:

### Answer

The values of are as follows:

### Answer only

The values of are as follows:

ax? +bx+c

ar? +bx+c=0

a, b, and c

ar? +bx+c=0

0.20== 85-x 0.20(85– x)=x? 17-0.20x = x? x +0.20x-17=0

0.20=- 85-X

ar? +bx+c=0

ar? +bx+c=0

ar? +bx+c=0

ar? +bx+c=0

r? +0.20x-17=0

a, b, and c

a=1 b=0.20 C=-17

ar? +bx+c=0

r? +0.20x-17=0

a, b, and c

a=1 b=0.20 C=-17

a, b, and c

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