Rearrange this expression into quadratic form, ax^2+bx+c = 0 0.20 = x^2/85-x a = 1, and identify the values of b and C. a = 1 b = 0.2 c = 11
Answer
General guidance
Concepts and reason
The quadratic polynomial is a second order polynomial of the form, 
. If this polynomial is to zero, then it is called quadratic equation.
In quadratic equation, 
, but b and c may equal to 0.
Fundamentals
The quadratic equation is in the form of 
, 
. Here, 
are the coefficients.
Step-by-step
Step 1 of 2
Rearrange the given expression as follows:
The given expression is as follows:
This equation is rearranged in the form of .
is 1. If it is not 1, then divide the whole equation with the coefficient of Step 2 of 2
Compare the equation with to get the values of b and c as follows:
The values of 
are as follows:
The values of are as follows:
The coefficients in the following two equations are compared to get the values of b and c:
Answer
The values of are as follows:
Answer only
The values of are as follows:
ax? +bx+c
ar? +bx+c=0
a, b, and c
ar? +bx+c=0
0.20== 85-x 0.20(85– x)=x? 17-0.20x = x? x +0.20x-17=0
0.20=- 85-X
ar? +bx+c=0
ar? +bx+c=0
ar? +bx+c=0
ar? +bx+c=0
r? +0.20x-17=0
a, b, and c
a=1 b=0.20 C=-17
ar? +bx+c=0
r? +0.20x-17=0
a, b, and c
a=1 b=0.20 C=-17
a, b, and c
We were unable to transcribe this image