Several reagents and several organic structures are shown below.
Construct a multistep synthetic route from the reactant
2-methyl-1-butene to the product 3-bromo-2-methyl-2-butanol by
dragging the appropriate pieces into the bins. Note that each bin
will hold only one item, and not every given reagent or structure
will be used.
Answer
General guidance
Conversion of 2-methyl-1-butene to 3-bromo-2-methyl-2-butanol occurs in three steps. They are,
1.Alkyl halide formation
2.Elimination
3.Halohydrin formation
Step-by-step
Step 1 of 3
The reaction is,
2-methylbut-1-ene reacts with 
to form 2-bromo-2-methylbutane.
for the more substituted bromo compound, because Step 2 of 3
The reaction is,
Potassium ethoxide is strong base, it reacts with 2-bromo-2-methylbutane to form 2-methylbut-2-ene. This is reaction is called elimination reaction.
Step 3 of 3
The reaction is,
Thus, the synthetic route is,
2-methylbut-2-ene reacts with 
to form 3-bromo-2-methyl-2-butanol.
for halohydrin formation, because it reacts with double bond to form dibromo substituted alkane. So, we don’t get the required product with 
.Answer
Thus, the synthetic route is,
Answer only
Thus, the synthetic route is,