Solve. 2x^2 + 16x + 50 = 0?

-3+/-4i

-2+/-+4i

-4+/-i

-4+/-3i

1 Answer

  • 2x^2+16x+50 = 0

    2(x^2+8x+25) = 0

    x^2+8x+25 = 0/2

    x^2+8x+25 = 0

    x = -b+-√(b^2-4ac)/(2a)

    x = -8+-√[(8^2-4(1)(25)]/[2(1)]

    x = -8+-√(64-100)/2

    x = -8+-√-36 / 2

    x = -8+-√36√-1 / 2

    x = -8+-6i/2

    x = -4+-3i

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