choose wisely
8 Answers
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5x+2y=10_3x+2y=6
Since 2y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2y from both sides.
5x=-2y+10_3x+2y=6
Divide each term in the equation by 5.
x=-(2(y-5))/(5)_3x+2y=6
Since the equation was solved for x, replace all occurrences of x in the other equations with the solution (-(2(y-5))/(5)).
x=-(2(y-5))/(5)_3(-(2(y-5))/(5))+2y=6
Multiply -2 by each term inside the parentheses.
x=((-2y+10))/(5)_3(-(2(y-5))/(5))+2y=6
Remove the parentheses around the expression -2y+10.
x=(-2y+10)/(5)_3(-(2(y-5))/(5))+2y=6
Divide each term in the numerator by the denominator.
x=-(2y)/(5)+(10)/(5)_3(-(2(y-5))/(5))+2y=6
Simplify each expression in -(2y)/(5)+(10)/(5).
x=-(2y)/(5)+2_3(-(2(y-5))/(5))+2y=6
Multiply -2 by each term inside the parentheses.
x=-(2y)/(5)+2_3(((-2y+10))/(5))+2y=6
Remove the parentheses around the expression -2y+10.
x=-(2y)/(5)+2_3((-2y+10)/(5))+2y=6
Divide each term in the numerator by the denominator.
x=-(2y)/(5)+2_3(-(2y)/(5)+(10)/(5))+2y=6
Simplify each expression in -(2y)/(5)+(10)/(5).
x=-(2y)/(5)+2_3(-(2y)/(5)+2)+2y=6
Multiply 3 by each term inside the parentheses.
x=-(2y)/(5)+2_(-(6y)/(5)+6)+2y=6
Reorder the polynomial -(6y)/(5)+6+2y alphabetically from left to right, starting with the highest order term.
x=-(2y)/(5)+2_-(6y)/(5)+2y+6=6
Find the LCD (least common denominator) of -(6y)/(5)+2y+0.
x=-(2y)/(5)+2_Least common denominator: 5
Multiply each term in the equation by 5 in order to remove all the denominators from the equation.
x=-(2y)/(5)+2_4y=0
Since the equation was solved for y, replace all occurrences of y in the other equations with the solution (0).
x=-(2y)/(5)+2_y=0
Since the equation was solved for y, replace all occurrences of y in the other equations with the solution (0).
x=-(2(0))/(5)+2_y=0
Multiply -2*0 to get 0 in the numerator.
x=(0)/(5)+2_y=0
Any expression with a factor of 0 in the numerator is equal to 0.
x=0+2_y=0
Remove the 0 from the polynomial; adding or subtracting 0 does not change the value of the expression.
x=2_y=0
This is the solution to the system of equations.
x=2_y=0
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5x+2y=10
(3x+2y=6) time this by -1
5x+2y=10
+(-3x)+(-2y)=(-6) add them up
2x=4 divide it by 2
x=2
now plug in the 2 for x to solve the y
5(2)+2y=10
10+2y=10 minus 10
2y=0
y=0
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Solve The System Algebraically
Source(s): https://shrinke.im/a80xZ -
x=2
y=0
You can solve this as a system of equations in the form Ax=b and find x with A^-1*b
A = [5 2; 3 2] (the coefficients of x and y)
b = [10; 6] (the results)
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5x + 2y = 10.........(i)
3x + 2y = 6..........(ii)
Subtract (ii) from (i), we get
(5x + 2y) −( 3x + 2y)= 10−6
or 2x = 4
hence x= 2
From (i) plugging the value of x, we get
5×2 + 2y = 10
10+ 2y = 10
2y=10−=0
Hence y= 0
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5x+2y=10
3x+2y=6
5x+2y=10
-1(3x+2y=6)
5x+2y=10
-3x-2y=-6
2x=4
x=2
y=0
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x = 2 & y=0..........
Source(s): i passed elementary school long back......... -
x = y