The combustion of propane (C3H8) in the presence of excess oxygen yields CO2 and H2O:
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)
When 7.3 g of C3H8 burns in the presence of excess O2, ____ g of CO2 is produced.
1 Answer
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7.3 g C3H8 x 1mole C3H8 / 44.0 g x 3 moles CO2/1mole C3H8 = 0.498 moles CO2
0.498 moles CO2 x 44.0 g CO2 / 1mole CO2 = 21.9 g CO2
Answer 22 grams with two significant figures.