The density of krypton gas at 1.21 atm and 50.0 degrees Celsius is _______g/L?

2 Answers

• One mole of Kr has a mass of 83.8 grams.

  At STP it would occupy 22.414 liters.

  At 1.21 atm and 50 C it will occupy

  (22.414 L) (1/1.21) (323.15/273.15) = still about 22 L, but use calculator.

  Then the density is 83.8 grams divided by (number of liters from previous line)

• Volume of 1 mole (83.8 g) of Kr = V = nRT/P

  V = 1 x 0.082057 x (50.0+273.15) / 1.21 atm

  V = 21.9 L

  g/L = 83.8 g / 21.9 L = 3.82 g/L