The formula of the ion of oxide that would be expected to form based on oxygen position in the periodic table?

5 Answers

• Are you referring to metal cations that form oxides with oxygen or are you asking what the symbol for oxide is? If your question is the latter, then oxide is O^2- and if so, I can explain in more detail if you'd like.

• Based on its position in Group 6 or16 (depending on the version you use) of the Periodic Table an oxygen atom will have 6 electrons in its last energy level/shell so requiring 2 more electrons, each with a charge of 1-, to make 8 and a full last energy level/shell. This will give it a charge of 2-

  Oxygen atom O Oxide ion O^2-

• when writing a chemical formula for an ion its net charge is written as a + or -. the way to figure out if its + or - is by looking at the # of protons and electrons. an ion is formed when an atom has one of its electrons stripped from its valence shell (outer shell) by a more electronegative atom. oxygen is one of the most electronegative so it has a tendency to strip electrons from others. stripping electrons causes the atom receiving the electron to become negatively charged bc there are more electrons (which have a charge of -1) than there are protons (which have a charge of +1). this negatively charged ion is called an anion. the atom that loses the electron has a positive charge bc it has more protons than electrons. a positively charged ion is a cation. the # that comes b4 the - or + depends on the difference between the # protons and electrons. if an atom has 2 electrons more than it does protons then ur charge is 2- (if its just 1 more then ur charge is just -) if it has 2 more protons than electrons then ur charge is 2+(once again if its only 1 more then its just +).

  atoms are always trying to complete there valence shell, this is y they create bonds. the # of electron shells an atom has depends on its # of electrons. an atom can only hold 2 electrons in its first shell, 8 in its 2nd shell, and 8 in its 3rd shell. so for atoms like hydrogen, that only have 1 electron, they only have 1 shell so that 1st shell is its valence shell. now since its valence shell can hold 2 electrons and it only has one, it will try to bond (share electrons) with another atom to complete its valence shell. the # of bonds an atom can make is determined by the # of electons it needs to complete its valence shell, this # is called its valence.

  now looking at the periodic table u see that the elements are placed in each row depending on their # of shells. oxygen is in the second row meaning it has 2 shells. using its electrons to check this, u see that it has 8 electrons meaning it contains 2 in its first shell and 6 in its second. since it needs 2 more electrons to finish its valence shell it has a valence of 2. it can bond w/ up to 2 atoms. since u are looking for a formula for an oxide ion and not a molecule, instead of sharing 2 electrons through bonds, oxygen is going to strip the electrons. since oxygen needs 2 electrons to reach 8 in its valence shell it is going to strip 2 electons. u now have an oxide ion that contains 2 more electrons than protons so it now has a charge of 2-. so writing this in a formula gives u O2- (the 2- is written to the top right of the O not beside it like here.) hope this wasnt too confusing.

  Source(s): college text book

• the formula of the ion of oxide that would be expected to form based on oxygen position in the periodic table is?

  In general:

  Atoms of elements in column 1 have 1 electron in their outer shell.

  Atoms of elements in column 2 have 2 electrons in their outer shell.

  Atoms of elements in column 3 have 3 electrons in their outer shell.

  Atoms of elements in column 4 have 4 electrons in their outer shell.

  Atoms of elements in column 5 have 5 electrons in their outer shell.

  Atoms of elements in column 6 have 6 electrons in their outer shell.

  Atoms of elements in column 7 have 7 electrons in their outer shell.

  Atoms of elements in column 8 have 8 electrons in their outer shell.

  Ions of these atoms are most stable when the outer shell contains 8 electrons. To become stable, the atoms will release or attract the specific number of electrons that will produce an ion with 8 electrons in its outer shell. This is called the Octet Rule.

  Atoms of elements in column 1 have 1 electron in their outer shell.

  Na → Na+1 + 1 e-

  Atoms of elements in column 2 have 2 electrons in their outer shell.

  Mg → Mg+2 + 2 e-

  Atoms of elements in column 13 have 3 electrons in their outer shell.

  Al → Al+3 + 3 e-

  Atoms of elements in column 14 have 4 electrons in their outer shell.

  Carbon compounds are covalent, so carbon shares its 4 electrons

  Atoms of elements in column 15 have 5 electrons in their outer shell.

  N + 3 e- → N-3

  Atoms of elements in column 16 have 6 electrons in their outer shell.

  O + 2 e- → O-2

  Atoms of elements in column 17 have 7 electrons in their outer shell.

  F + 1 e- → F-1

  Atoms of elements in column 18 have 8 electrons in their outer shell, so atoms of elements in column 8 are stable, so atoms in column 18 do not attract or release electrons.

  Atoms of elements in column 8 do not form ions!!

  I hope this helps!!

• i believe one of the many possible ones is

  there is O

  O2 dioxide

  O3 ozone

  O4 undeterman at this time because in most chemistry books its more theroical then anything at this time