# The formula of the ion of oxide that would be expected to form based on oxygen position in the periodic table?

the formula of the ion of oxide that would be expected to form based on oxygen position in the periodic table is?

I totally don't get this at all! HELP PLEASE?!

### 5 Answers

• Are you referring to metal cations that form oxides with oxygen or are you asking what the symbol for oxide is? If your question is the latter, then oxide is O^2- and if so, I can explain in more detail if you'd like.

• Based on its position in Group 6 or16 (depending on the version you use) of the Periodic Table an oxygen atom will have 6 electrons in its last energy level/shell so requiring 2 more electrons, each with a charge of 1-, to make 8 and a full last energy level/shell. This will give it a charge of 2-

Oxygen atom O Oxide ion O^2-

• when writing a chemical formula for an ion its net charge is written as a + or -. the way to figure out if its + or - is by looking at the # of protons and electrons. an ion is formed when an atom has one of its electrons stripped from its valence shell (outer shell) by a more electronegative atom. oxygen is one of the most electronegative so it has a tendency to strip electrons from others. stripping electrons causes the atom receiving the electron to become negatively charged bc there are more electrons (which have a charge of -1) than there are protons (which have a charge of +1). this negatively charged ion is called an anion. the atom that loses the electron has a positive charge bc it has more protons than electrons. a positively charged ion is a cation. the # that comes b4 the - or + depends on the difference between the # protons and electrons. if an atom has 2 electrons more than it does protons then ur charge is 2- (if its just 1 more then ur charge is just -) if it has 2 more protons than electrons then ur charge is 2+(once again if its only 1 more then its just +).

atoms are always trying to complete there valence shell, this is y they create bonds. the # of electron shells an atom has depends on its # of electrons. an atom can only hold 2 electrons in its first shell, 8 in its 2nd shell, and 8 in its 3rd shell. so for atoms like hydrogen, that only have 1 electron, they only have 1 shell so that 1st shell is its valence shell. now since its valence shell can hold 2 electrons and it only has one, it will try to bond (share electrons) with another atom to complete its valence shell. the # of bonds an atom can make is determined by the # of electons it needs to complete its valence shell, this # is called its valence.

now looking at the periodic table u see that the elements are placed in each row depending on their # of shells. oxygen is in the second row meaning it has 2 shells. using its electrons to check this, u see that it has 8 electrons meaning it contains 2 in its first shell and 6 in its second. since it needs 2 more electrons to finish its valence shell it has a valence of 2. it can bond w/ up to 2 atoms. since u are looking for a formula for an oxide ion and not a molecule, instead of sharing 2 electrons through bonds, oxygen is going to strip the electrons. since oxygen needs 2 electrons to reach 8 in its valence shell it is going to strip 2 electons. u now have an oxide ion that contains 2 more electrons than protons so it now has a charge of 2-. so writing this in a formula gives u O2- (the 2- is written to the top right of the O not beside it like here.) hope this wasnt too confusing.

• the formula of the ion of oxide that would be expected to form based on oxygen position in the periodic table is?

In general:

Atoms of elements in column 1 have 1 electron in their outer shell.

Atoms of elements in column 2 have 2 electrons in their outer shell.

Atoms of elements in column 3 have 3 electrons in their outer shell.

Atoms of elements in column 4 have 4 electrons in their outer shell.

Atoms of elements in column 5 have 5 electrons in their outer shell.

Atoms of elements in column 6 have 6 electrons in their outer shell.

Atoms of elements in column 7 have 7 electrons in their outer shell.

Atoms of elements in column 8 have 8 electrons in their outer shell.

Ions of these atoms are most stable when the outer shell contains 8 electrons. To become stable, the atoms will release or attract the specific number of electrons that will produce an ion with 8 electrons in its outer shell. This is called the Octet Rule.

Atoms of elements in column 1 have 1 electron in their outer shell.

Na â Na+1 + 1 e-

Atoms of elements in column 2 have 2 electrons in their outer shell.

Mg â Mg+2 + 2 e-

Atoms of elements in column 13 have 3 electrons in their outer shell.

Al â Al+3 + 3 e-

Atoms of elements in column 14 have 4 electrons in their outer shell.

Carbon compounds are covalent, so carbon shares its 4 electrons

Atoms of elements in column 15 have 5 electrons in their outer shell.

N + 3 e- â N-3

Atoms of elements in column 16 have 6 electrons in their outer shell.

O + 2 e- â O-2

Atoms of elements in column 17 have 7 electrons in their outer shell.

F + 1 e- â F-1

Atoms of elements in column 18 have 8 electrons in their outer shell, so atoms of elements in column 8 are stable, so atoms in column 18 do not attract or release electrons.

Atoms of elements in column 8 do not form ions!!

I hope this helps!!

• i believe one of the many possible ones is

there is O

O2 dioxide

O3 ozone

O4 undeterman at this time because in most chemistry books its more theroical then anything at this time