The position of a particle is given by the function x=(2t3−9t2+12)m. where t is in s.

The position of a particle is given by x2t39t2 +12 1) The velocity of the particle is dx dt 1)-18 dt Given that v, 0 6t2 - 18t 0 2) The position of the particle at t0 is x-23 - 9t2 +12 = 2(0)3-9(0)2 +12=12 m The position of the particle at t 3 s is x = 2t3-9t2 +12 2(3 s) -9(3 s)2 + 12-_15 m