The rate of disappearance of HBr in the gas phase reaction
2HBr(g)=====H2(g) + Br2(g)
is 0.130 M/s at 150°C. The rate of reaction is __ M/s
1 Answer
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Divide the rate of disappearance of HBr by its coefficient in the balanced equation to get the rate of the reaction:
0.130 M/s / 2 = 0.065 M/s
