Transforming Formulas: 1/a+1/b=1/c. Solve for c.?

8 Answers

• abc[1/a+1/b=1/c]

  bc+ac=ab

  c(b+a)=ab

  c=ab/(a+b)

• 1/a - 1/b = 1/c

• 1/a + 1/b = 1/c

  c(1/a + 1/b) = 1

  c/a + c/b = 1

  (ca + cb)/ab = 1

  ca + cb = ab

  c(a + b) = ab

  c = ab/(a + b)

  Answer: c = ab/(a + b)

  Checking equality of sides: substitute c with ab/(a + b):

  1/a + 1/b = 1/(ab/[a + b])

  1/a + 1/b = (a + b)/ab

  ab(1/a + 1/b) = a + b

  b + a = a + b

• Solve For C

  Source(s): https://shrinke.im/a8mOi

• 1/a + 1/b = 1/c

  (b + a)/ab = 1/c

  c = ab/(a + b)

• 1/a + 1/b = 1/c

  Multiply all terms by abc

  bc + ac = ab

  c(b+a) = ab

  c = ab / (a+b)

• c=ab/(a+b)

• c/a+c/b=1

  2c/

  Source(s): i am bored