Use the Laplace transform to solve the given initial value
problem:
y'' + 3y' + 2y = 0 y(0)=1, y'(0)=0
Answer
so that s2 + 3s 2 Expanding this last term in partial fractions gives so that A(s + 1) + B(s+2) = s+ 3 Plugging in s =-2 gives A =-1 and plugging in s =-1 gives B = 2. Therefore s +2