What are the exact solutions of x2 − 3x − 7 = 0?

6 Answers

• b^2-A(a)(c)

  b= -3

  a= 1

  c= 7

  (-3)^2 - 4 (1)(-7)

  9+28

  =37

  sqrt(b^2 - 4(a)(c))=sqrt(37)

  X= -b±sqrt(b^2 - 4(a)(c))

  ------------------------------

  2a

  X= 3±sqrt(37)

  -------------

  2

  X=3+sqrt(37)

  ------------------

  2

  X=3-sqrt(37)

  ---------------

  2

• x2 - 3x - 7 = 0

  (x - 3/2)^2 - 37/4 = 0

  Solutions:

  x = (3 - sqrt37)/2

  x = (3 + sqrt37)/2

• when Ax^2 + Bx + C = 0, then x = (-B +/- Sqrt(B^2 - 4AC)) / 2A

  For your equation, A = 1, B = -3, and C = -7

  x = (3 +/- Sqrt((-3)^2 - 4(1)(-7))) / (2(1))

  x = (3 +/- Sqrt(9 +28)) / 2

  x = (3 +/- Sqrt(37)) / 2

• I assume it's x^2 - 3x - 7 = 0

  Use quadratic formula [-b +- sqrt (b^2 - 4ac)]/2a

  =(-(-3) +- sqrt ((3)^2 - 4(1)(-7))) / 2(1)

  = (9 + sqrt 37)/2 OR (9 - sqrt 37)/2

  = (9 + 6.083)/2 OR (9 - 6.083)/2

• x1 = 3/2 + (1/2)*sqrt(37)

  x2 = 3/2 - (1/2)*sqrt(37)

  Source(s): Maple 15

• x = [ - b ± √ ( b ² - 4 a c ) ] / 2 a

  x = [ 3 ± √ ( 9 + 28 ) ] / 2

  x = [ 3 ± √ 37 ] / 2