What is the angle between the given vector and the positive
direction of the x-axis? (Round your answer to the nearest degree.
i +sqrt(15) j
Answer
75.52
θ=tan-1(√15)=76 degree
i + √15j
θ = tan-1(√15/1) = 75.52
What is the angle between the given vector and the positive
direction of the x-axis? (Round your answer to the nearest degree.
i +sqrt(15) j
75.52
θ=tan-1(√15)=76 degree
i + √15j
θ = tan-1(√15/1) = 75.52