
What pressure will 0.44 moles of CO2 exert in a 2.6L container at 25°C? R=0.0821 atm·L/mol K A) 0.35 atm B) 4.1 atm C) 4.7 atm D) 8.6 atm E) 3.6 atm A B ОС OD О Е
Answer
Mole = 0.44
V = 2.6 L
Temperature = 25°C = 25 + 273 = 298 K
R = 0.0821
according to ideal gas equation
PV = nRT
P = nRT / V
= 0.44 * 0.0821* 298 / 2.6
= 4.1 atm
Correct answer :- b