When 155 mL of water at 26 degrees C is mixed with 75 mL of water at 85 degrees C, what is the final temp?

Could someone SHOW me the steps to working this one out.

Assume no heat is lost to the surroundings, d of water is 1 g/mol

3 Answers

  • 155ml(1g/ml) = 155g H2O

    75ml(1g/ml) = 75g H2O

    (mc∆t) = - [(mc∆t)]

    (155g)(4.184J/g•℃)(tf - 26℃) = - [(75g)(4.184J/g•℃)(tf - 85℃)

    648.52tf - 16861.52 = -[313.8tf - 26673]

    962.32tf = 43534.52

    tf = 45℃

  • I forget, so I might be wrong about this. Use this equation:

    Q1 = Q2

    m1Cp(Tf-T1) = m2Cp(T2-Tf)

    m1(Tf-T1) = m2(T2-Tf) Cp cancels on both sides


    m1 and m2 are the masses of the different waters, so you will need the density of water to determine this: d = m/V. You have both volumes:

    V1 = 155 mL

    V2 = 75 mL

    T1 = 26 C

    T2 = 85 C

    Solve for Tf = final temperature.

  • 2,4,6-Tris(carbamoylmethylamino)-1,3,5-s-triazine, abbreviated TCMT, is prepared by the reaction of 2,4,6-tris(carbethoxymethylamino)-1,3,5-s-triazine with ammonia. The methylol derivative of TCMT is prepared and applied to cotton textiles and blends of cotton and polyester to impart wrinkle recovery theret

Leave a Reply

Your email address will not be published. Required fields are marked *

Related Posts