A uniform stick 1.3 m long with a total mass of 220 g is pivoted at its center. A 3.8-g bullet is shot through the stick midway between the pivot and one end The bullet approaches at 250 m/s and leaves at 140 m/s.
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1 Answer
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Is=.220*1.3^2/12
0.031
Ib=3.8*(1.3/4)^2/1000
0.0004
0.00042504/1.3=
0.00041404/1.3+0.031*ω
solve for ω
ω=0.031/(0.00041104/1.3)
0.229 rad/s
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